Question : The smallest five-digit number that is divisible by 12, 18 and 21 is:
Option 1: 10224
Option 2: 30256
Option 3: 10080
Option 4: 50321
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Correct Answer: 10080
Solution :
We know the smallest five-digit number is 10000
LCM of (12,18, 21) = 252
Now, dividing 10000 by 252, we get a remainder of 172.
So, the required smallest five-digit number
= 10000 + (252 - 172)
= 10000 + 80
= 10080
Hence, the correct answer is 10080.
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