the solution of (x3-2y3)dx+3xy2dy=0 is??
Answer (1)
Student Expert
8th May, 2019
Hi Sridevi,
I suppose you want to know the value of dy/dx as you have not mentioned what you want to know
If yes, Then
(x3-2y3)dx = -3xy2dy
-3xy2dy = (x3-2y3)dx
dy = (x3-2y3)dx / (-3xy2dy)
dy/dx = (x3-2y3) / (-3xy2)
Which is your required answer :)
I suppose you want to know the value of dy/dx as you have not mentioned what you want to know
If yes, Then
(x3-2y3)dx = -3xy2dy
-3xy2dy = (x3-2y3)dx
dy = (x3-2y3)dx / (-3xy2dy)
dy/dx = (x3-2y3) / (-3xy2)
Which is your required answer :)
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