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the solution of (x3-2y3)dx+3xy2dy=0 is??


Sridevi Jinna 1st May, 2019
Answer (1)
Sk Student Expert 8th May, 2019
Hi Sridevi,

I suppose you want to know the value of dy/dx as you have not mentioned what you want to know

If yes, Then

(x3-2y3)dx = -3xy2dy

-3xy2dy = (x3-2y3)dx

dy = (x3-2y3)dx / (-3xy2dy)

dy/dx = (x3-2y3) / (-3xy2)

Which is your required answer :)






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