Question : The speed of a car going from A to B is 110 km/hr while coming back, its speed is 76 km/hr. What is the average speed during the entire journey?
Option 1: $87 \frac{81}{99} \mathrm{~km} / \mathrm{hr}$
Option 2: $83 \frac{89}{93} \mathrm{~km} / \mathrm{hr}$
Option 3: $89 \frac{83}{93} \mathrm{~km} / \mathrm{hr}$
Option 4: $82 \frac{91}{97} \mathrm{~km} / \mathrm{hr}$
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Correct Answer: $89 \frac{83}{93} \mathrm{~km} / \mathrm{hr}$
Solution :
The speed of a car going from A to B is 110 km/hr while coming back, its speed is 76 km/hr.
Let $a=110$ and $b=76$
So, the average speed in this journey $=\frac{2ab}{a+b}=\frac{2×110×76}{110+76}=\frac{8360}{93}=89 \frac{83}{93}\mathrm{\ km/hr}$
Hence, the correct answer is $89\frac{83}{93}\mathrm{\ km/hr}$.
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