the strengthog magnetic field is increased by 21% the frequency of magnetic needle
Answer (1)
Student Expert
12th Aug, 2019
Dear student, first of all we will find the time period and 1/T is frequency.
So, we know that the time period of any oscillating thing is given by
T = 2 × pi × sqrt( I/M*B)
Now, frequency, f =1/T
=>(1/2*pi)×sqrt( M*B/I)
Now in the above equation 2*pi, I amd M are constant. Therefore,
f is directly proportional to B.
Now applying the formula -
((f2/f1) - 1)×100 =((B2/B1) - 1)×100
In the question its given that the increase is by 21% so putting this value on the right hand side
((f2/f1) - 1)×100 =10%
So the frequency of magnetic needle will be 10%.
All the best
Hope this helps
Comments (0)
Related Questions
Trending Articles/News
JEE Advanced 2025 Latest News and Updates
4 minutes ago
How Many Students Took CAT 2024 Exam?
9 minutes ago
