Question : The sum of four consecutive even numbers is 748. The smallest among them is:
Option 1: 188
Option 2: 186
Option 3: 184
Option 4: 174
Correct Answer: 184
Solution : Given: The sum of four consecutive even numbers is 748. Let the smallest number be $n$. Then, the four consecutive even numbers are $n, n+2, n+4, n+6$. According to the question, $n+(n+2)+(n+4)+(n+6) = 748$ or, $4n + 12 = 748$ or, $4n = 748 – 12 = 736$ or, $n = \frac{736}{4} = 184$ Hence, the the smallest number is $184$.
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