9 Views

Question : The sum of squares of 3 consecutive positive numbers is 365. The sum of the numbers is:

Option 1: 30

Option 2: 33

Option 3: 36

Option 4: 45


Team Careers360 8th Jan, 2024
Answer (1)
Team Careers360 11th Jan, 2024

Correct Answer: 33


Solution : Let the numbers be $n–1, n$ and $n+1$.
$(n–1)^{2} + (n)^{2} + (n+1)^{2} = 365$
or, $n^2 – 2n+1+n^2+n^2+2n+1 = 365$
or, $3n^2 = 365–2$
or, $3n^2 = 363$
or, $n^2 = 121$
or, $n = 11$
So, 10, 11 and 12 are the numbers.
Their sum is (10 + 11 + 12) = 33
Hence, the correct answer is 33.

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books