Question : Let $x$ be the least number which, when divided by 5, 6, 7, and 8, leaves a remainder of 3 in each case, but when divided by 9, leaves no remainder. The sum of the digits of $x$ is:

Option 1: 21

Option 2: 22

Option 3: 18

Option 4: 24

Question : If a certain number of two digits is divided by the sum of its digits, the quotient is 6 and the remainder is 3. If the digits are reversed and the resulting number is divided by the sum of the digits, the quotient is 4 and the remainder is 9. The sum of the digits of the number is:

Option 1: 6

Option 2: 9

Option 3: 12

Option 4: 4

Question : Find the least number which when divided by 12, 18, 24, and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

Option 1: 366

Option 2: 364

Option 3: 384

Option 4: 634

Question : Find the least number which when divided separately by 15, 20, 36 and 48 leaves 3 as the remainder in each case.

Option 1: 183

Option 2: 243

Option 3: 483

Option 4: 723

Question : A number, when divided by 6, leaves a remainder of 3. When the square of the same number is divided by 6, the remainder is:

Option 1: 0

Option 2: 2

Option 3: 1

Option 4: 3