Question : The sum of the interior angles of a regular polygon A is 1260 degrees and each interior angle of a regular polygon B is $128 \frac{4}{7}$ degrees. The sum of the number of sides of polygons A and B is:
Option 1: 17
Option 2: 16
Option 3: 19
Option 4: 18
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: 16
Solution :
The sum of the interior angle Polygon A = 1260°
If the sides of the polygon A are n
A
.
⇒ (n
A
– 2) × 180° = 1260°
⇒ (n
A
– 2) = $\frac{1260°}{180°}$ = 7
⇒ n
A
= (7 + 2) = 9
Each interior angle of a regular polygon B = $\frac{900}{7}$
If the sides of the polygon B are n
B
.
⇒ 180° × (n
B
– 2) = $\frac{900}{7}$ × n
B
⇒ 180n
B
– $\frac{900}{7}$ × n
B
= 360
⇒ $\frac{360}{7}$ × n
B
= 360
$\therefore$ n
B
= 7
The sum of sides of polygons A and B = 7 + 9 = 16
Hence, the correct answer is 16.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
