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Question : The sum of the squares of three positive numbers is 323. If the sum of the squares of two numbers is twice the third, their product is:

Option 1: 255

Option 2: 260

Option 3: 275

Option 4: 270


Team Careers360 22nd Jan, 2024
Answer (1)
Team Careers360 23rd Jan, 2024

Correct Answer: 255


Solution :
Let the three numbers be a, b and c.
According to the question,
a 2 + b 2 + c 2 = 323 and a 2 + b 2 = 2c
⇒ c 2 + 2c = 323
⇒ c 2 + 2c – 323 = 0
⇒ (c + 19) (c – 17) = 0
Taking, c = 17 as c can't be negative.
⇒ a 2 + b 2 = 2c
⇒ a 2 + b 2 = 2 × 17
⇒ a 2 + b 2 = 34
⇒ a 2 + b 2 = 25 + 9
⇒ a 2 + b 2 = 5 2 + 3 2
Comparing both sides we get, a = 5 and b = 3 (taking a > b)
So, the product of a, b, and c = 3 × 5 × 17 = 255
Hence, the correct answer is 255.

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