Question : The sum of two numbers is 680. If the bigger number is decreased by 15% and the smaller number is increased by 15%, then the resultant numbers are equal. Find the smaller number.
Option 1: 307
Option 2: 285
Option 3: 289
Option 4: 304
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 289
Solution : Let the bigger number be $x$. Smaller number = $680 - x$ According to the question, $x(1 - 15\%) = (680 - x)(1 + 15\%)$ ⇒ $\frac{x}{(680 - x)} = \frac{23}{17}$ ⇒ $17x = 23 × 680 - 23x$ ⇒ $40x = 23 × 680$ ⇒ $x = 23 × 17$ ⇒ $x = 391$ So, the smaller number = 680 – 391 = 289 Hence, the correct answer is 289.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : The sum of three positive numbers is 18 and their product is 162. If the sum of two numbers is equal to the third number, then the sum of the squares of the numbers is:
Question : The sum of three positive numbers is 18 and their product is 162. If the sum of two numbers is equal to the third number, the sum of the squares of the numbers is:
Question : If the sum of squares of two real numbers is 41 and their sum is 9, then the sum of cubes of these two numbers is:
Question : The sum of the cubes of two numbers is 793. The sum of the numbers is 13. Then the difference between the two numbers is:
Question : The average of n numbers is 45. If 60% of the numbers are increased by 5 each and the remaining numbers are decreased by 10 each, then what is the average of the numbers so obtained?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile