Question : The table given below shows the marks obtained by boys and girls in different subjects.
| Subjects | Boys | Girls |
| A | 60 | 120 |
| B | 80 | 100 |
| C | 140 | 40 |
| D | 120 | 60 |
| E | 100 | 40 |
L1 = The difference between marks obtained by boys and girls in all subjects.
L2 = The value of the average of marks obtained by boys in C, D, and E.
What is the value of (L1 – L2)?
Option 1: 40
Option 2: 20
Option 3: 10
Option 4: 50
Correct Answer: 20
Solution :
The difference between marks obtained by boys and girls in all subjects, L1 = (60 + 80 + 140 + 120 + 100) – (120 + 100 + 40 + 60 + 40)
⇒ L1 = 500 – 360 = 140
$\text{Average}=\frac{\text{Sum of all the values}}{\text{Number of all the values}}$
The value of the average of marks obtained by boys in C, D, and E
= L2 = $\frac{140+120+100}{3}= \frac{360}{3}$ = 120
The value of L1 – L2 = 140 – 120 = 20
Hence, the correct answer is 20.
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