Question : The table given below shows the number of sharpeners sold by two shopkeepers A and B in 5 months.
| Shopkeeper | ||
| Months | A | B |
| R | 200 | 155 |
| S | 190 | 160 |
| T | 170 | 210 |
| U | 165 | 180 |
| V | 155 | 175 |
$P1$ = The total number of sharpeners sold by A.
$P2$ = The total number of sharpeners sold by B.
What is the value of $\frac{P1}{P2}$?
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
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Correct Answer: 1
Solution :
As per the given graph,
$P1$ (total sharpeners sold by A) = 200 + 190 + 170 + 165 + 155 = 880
$P2$ (total sharpeners sold by B) = 155 + 160 + 210 + 180 + 175 = 880
So, the value of $\frac{P1}{P2}$ = $\frac{880}{880}$ = 1
Hence, the correct answer is 1.
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