Question : The table given below shows the production of bikes by two companies in 6 years.
J1 = The value of average production of the bike by A in years P, Q, R, and S. J2 = The value of average production of bikes by B in years T and U. What is the value of $\frac{J1}{J2}$?
Option 1: 3
Option 2: 4
Option 3: 1
Option 4: 2
New: SSC MTS 2024 Application Form OUT; Direct Link
Don't Miss: Month-wise Current Affairs | Upcoming Government Exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 3
Solution : Use the formula, Average = $\frac{\text{Sum of values}}{\text{The total values}}$ J1 $=$ The value of average production of the bike by A in years P, Q, R, and S $=\frac{300+150+250+500}{4}=\frac{1200}{4}=300$ J2 $=$ The value of average production of bikes by B in years T and U $=\frac{50+150}{2}=\frac{200}{2}=100$ So, the value of $\frac{J1}{J2}=\frac{300}{100}=3$ Hence, the correct answer is 3.
Application | Cutoff | Selection Process | Preparation Tips | Eligibility | Exam Pattern | Admit Card
Question : The table given below shows the production of television and fridges by different companies.
Question : The table given below shows the demand and production of five articles.
Question : The table given below shows the marked price and discount percentage of five different articles.
Question : The table given below shows the marked price and selling price of 6 articles.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile