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Question : The table given below shows the production of bikes by two companies in 6 years.

Years A B
P 300 550
Q 150 400
R 250 300
S 500 100
T 350 50
U 200 150

J1 = The value of average production of the bike by A in years P, Q, R, and S.
J2 = The value of average production of bikes by B in years T and U.
What is the value of $\frac{J1}{J2}$?

Option 1: 3

Option 2: 4

Option 3: 1

Option 4: 2


Team Careers360 6th Jan, 2024
Answer (1)
Team Careers360 14th Jan, 2024

Correct Answer: 3


Solution : Use the formula, Average = $\frac{\text{Sum of values}}{\text{The total values}}$
J1 $=$ The value of average production of the bike by A in years P, Q, R, and S
$=\frac{300+150+250+500}{4}=\frac{1200}{4}=300$
J2 $=$ The value of average production of bikes by B in years T and U
$=\frac{50+150}{2}=\frac{200}{2}=100$
So, the value of $\frac{J1}{J2}=\frac{300}{100}=3$
Hence, the correct answer is 3.

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