Question : The table given below shows the production of bikes by two companies in 6 years.
| Years | A | B |
| P | 300 | 550 |
| Q | 150 | 400 |
| R | 250 | 300 |
| S | 500 | 100 |
| T | 350 | 50 |
| U | 200 | 150 |
J1 = The value of average production of the bike by A in years P, Q, R, and S.
J2 = The value of average production of bikes by B in years T and U.
What is the value of $\frac{J1}{J2}$?
Option 1: 3
Option 2: 4
Option 3: 1
Option 4: 2
Correct Answer: 3
Solution :
Use the formula, Average = $\frac{\text{Sum of values}}{\text{The total values}}$
J1 $=$ The value of average production of the bike by A in years P, Q, R, and S
$=\frac{300+150+250+500}{4}=\frac{1200}{4}=300$
J2 $=$ The value of average production of bikes by B in years T and U
$=\frac{50+150}{2}=\frac{200}{2}=100$
So, the value of $\frac{J1}{J2}=\frac{300}{100}=3$
Hence, the correct answer is 3.
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