Question : The table given below shows the sales of bikes and cars of five companies.
| Companies | Bike | Car |
| P | 200 | 1200 |
| Q | 100 | 300 |
| R | 500 | 700 |
| S | 600 | 1000 |
| T | 800 | 800 |
$J_1$ = The average sale of bikes of companies P, Q, and R.
$J_2$ = The average sale of cars of companies R, S, and T.
What is the value of ($J_1:J_2$)?
Option 1: 24 : 11
Option 2: 8 : 25
Option 3: 7 : 24
Option 4: 25 : 8
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Correct Answer: 8 : 25
Solution :
$J_1$ = The average sale of bikes of companies P, Q, and R
= $\frac{200+100+500}{3}$ = $\frac{800}{3}$
$J_2$ = The average sale of cars of companies R, S, and T
= $\frac{700+1000+800}{3}$ = $\frac{2500}{3}$
So, $J_1:J_2$ = $\frac{800}{3}:\frac{2500}{3}$ = 8 : 25
Hence, the correct answer is 8 : 25.
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