Question : The table given below shows the sales of bikes and cars of five companies.
$J_1$ = The average sale of bikes of companies P, Q, and R. $J_2$ = The average sale of cars of companies R, S, and T. What is the value of ($J_1:J_2$)?
Option 1: 24 : 11
Option 2: 8 : 25
Option 3: 7 : 24
Option 4: 25 : 8
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Correct Answer: 8 : 25
Solution : $J_1$ = The average sale of bikes of companies P, Q, and R = $\frac{200+100+500}{3}$ = $\frac{800}{3}$ $J_2$ = The average sale of cars of companies R, S, and T = $\frac{700+1000+800}{3}$ = $\frac{2500}{3}$ So, $J_1:J_2$ = $\frac{800}{3}:\frac{2500}{3}$ = 8 : 25 Hence, the correct answer is 8 : 25.
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