Question : The tens digit of a two-digit number is larger than the unit digit by 7. If we subtract 63 from the number, the new number obtained is a number formed by the interchange of the digits. Find the number.
Option 1: 81
Option 2: 18
Option 3: 62
Option 4: 26
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Correct Answer: 81
Solution : Let the number be $(10x + y)$. According to the question, $x > y$ ⇒ $x - y = 7$ Now, ⇒ $(10x + y) - 63 =10y + x$ Options 1, 2, 3 i.e. (18, 62, 26) is lesser than 63, so we will get the values in negative integer. Hence, the correct answer is 81.
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