Hi
Let the first term of a G.P is a while r is the common ratio. Then, The First 5 terms of G.P will be given by a,ar, ar^2,ar^3,ar^4 Then, ∴ Third term of the GP=ar^2 Now, we have Product of first five terms = a*(ar)*(ar^2)*(ar^3)*(ar^4) = a^5r^10 = (ar^2)^5 = 4^5 = 1024. Thus , the product of first 5 terms is 1024
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Question : What is the sum of the first 9 terms of an arithmetic progression, if the first term is 7 and the last term is 55?
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