Question : The three sides of a triangle are 9, 24, and S units. Which of the following is correct?
Option 1: $15 < S < 33$
Option 2: $15 \leq S<33$
Option 3: $15<S\leq 33$
Option 4: $15 \leq S \leq 33$
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $15 < S < 33$
Solution : It is a property of a triangle that the sum of the lengths of any two sides of a triangle is always greater than the length of the third side. So according to the question : $\therefore$ 9 + 24 > S ⇒ S < 33 Also 24 – 9 < S ⇒ S < 15 $\therefore$ 15 < S < 33 Hence, the correct answer is $15<S<33$.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : If the square of the product of three sides of the triangle is 1024 units and the area of its circumcircle is $16 \pi$, what is the area of the given triangle?
Question : The sides of a triangle are in the ratio 7 : 9 : 12. The difference between the lengths of the largest and smallest sides is 15 cm. The length of the largest side would be (in cm):
Question : The radius of the incircle of a triangle whose sides are 9 cm, 12 cm, and 15 cm is:
Question : The sides of a triangle are 9 cm, 6 cm, and 5 cm. What is the value of the circumradius of this triangle?
Question : Three angles of a triangle are $(x-15^{\circ}),(x+45^{\circ}),$ and $(x+60^{\circ})$. Identify the type of triangle.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile