The torque of force F = 2i -3j +4k newton acting at the point r =3i +2k +3k metre about origin is (in N-m) a).6i-6j +12k b).17i - 6j -13k c).-6i +6k -12k d).-17i +6j +13k
Answer (1)
17th Mar, 2021
Dear aspirant,
For this question you just simply need to apply the formula for torque which is r×F where r = (3-0)i +(2-0)j+(3-0)k and F=(2i-3j+4k) , just do the normal cross product calculations which will give you 17i -6j-13k. This is your final torque expression.
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