Question : The total surface area of a right pyramid on a square base of side 10 cm with height 12 cm is:
Option 1: 260 cm2
Option 2: 360 cm2
Option 3: 330 cm2
Option 4: 300 cm2
Correct Answer: 360 cm 2
Solution : In $\triangle$OAB, Slant height, $l$ = $\sqrt {h^2 + AB^2}$ = $\sqrt {12^2 + 5^2}$ = $\sqrt{169}$ = $13$ cm Total surface area = lateral surface area + area of the base = $\frac{1}{2}$ × perimeter of base × slant height + area of the base = $\frac{1}{2} × (4 × 10) × 13 + 10^2$ = $260+100$ = $360$ cm 2 Hence, the correct answer is 360 cm 2 .
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