The unit vector along I + j is 1).k 2).i + j 3).I + j/ under root2 4).I + j/2
Answer (1)
4th Jan, 2021
We know that Unit vector is given by => Vector/(Magnitude of the vector)
Now the given vector is i+j
Magnitude of the vector is squareroot(1+1)=squareroot(2)
Thus, the unit vector=> i+j/(square root 2)
Goodnight :)
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