The unit vector along I + j is 1).k 2).i + j 3).I + j/ under root2 4).I + j/2

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The unit vector along I + j is 1).k 2).i + j 3).I + j/ under root2 4).I + j/2

nafeesahmad0616 4th Jan, 2021

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Answer (1)

Subhrajit Mukherjee 4th Jan, 2021

We know that Unit vector is given by => Vector/(Magnitude of the vector)

Now the given vector is i+j

Magnitude of the vector is squareroot(1+1)=squareroot(2)

Thus, the unit vector=> i+j/(square root 2)

Goodnight :)

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nafeesahmad0616

4th Jan, 2021

thank you sir

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