Question : The value of (16 + 14) ÷ 2 – 12 + 16 × 4 – 28 + 13 (–16 + 13) is:
Option 1: 6
Option 2: 0
Option 3: –3
Option 4: 3
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 0
Solution : Given: (16 + 14) ÷ 2 – 12 + 16 × 4 – 28 + 13 (–16 + 13) Using the BODMAS rule we get, = 30 ÷ 2 – 12 + 16 × 4 – 28 + 13 (–3) = 15 – 12 + 64 – 28 – 39 = 3 + 64 – 67 = 0 Hence, the correct answer is 0.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : Directions: By interchanging the given two signs which of the following equations will be correct? × and –
Question : What is the value of $6-(6\div 2-3+7-2) \times[\{3-2 \div 2\} \times 5-6]?$
Question : Directions: By interchanging the given two signs which of the following equations will be not correct? – and ×
Question : Directions: If + means ÷, – means +, × means –, and ÷ means ×, what will be the value of the following expression? [{(38 × 23) – (4 ÷ 3)} + (6 – 3)] ÷ 2
Question : Simplify the following expression: [$\sqrt{25}$ + 12 ÷ 3 – {20 + (16 of 8 ÷ 16) – (54 ÷ 18 of $\frac{1}{2}$}]
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile