Question : The value of $\frac{3+8 \times 8 \div 8 \text { of } 8+7 \div 7 \times 2}{5 \div 5 \text { of } 4+3 \times 3 \div 3-3+2}$ is:
Option 1: $1 \frac{3}{5}$
Option 2: $2 \frac{2}{3}$
Option 3: $1 \frac{4}{7}$
Option 4: $2 \frac{3}{7}$
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Correct Answer: $2 \frac{2}{3}$
Solution :
Given: $\frac{3+8 \times 8 \div 8 \text { of } 8+7 \div 7 \times 2}{5 \div 5 \text { of } 4+3 \times 3 \div 3-3+2}$
$=\frac{3+8 \times \frac{8}{64}+\frac{7}{7}\times 2}{\frac{5}{20}+3 \times \frac{3}{3}-3+2}$
$= \frac{3+1+1 \times 2}{\frac{1}{4}+3 \times 1-3+2}$
$=\frac{3+1+2}{\frac{1}{4}+2}$
$=\frac{6}{\frac{9}{4}}$
$= \frac{8}{3}$
$= 2\frac{2}{3}$
Hence, the correct answer is $2\frac{2}{3}$.
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