Question : The value of $(0.3)^{[\frac {(200-146)}{(3 \times 3 \times 3)}-3]}$ is:
Option 1: $\frac{10}{3}$
Option 2: $\frac{5}{3}$
Option 3: $\frac{7}{3}$
Option 4: $\frac{8}{3}$
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Correct Answer: $\frac{10}{3}$
Solution : Given: $(0.3)^{[\{\frac{(200-146)}{(3 \times 3 \times 3)}\}-3]}$ = $(0.3)^{[\{\frac{54}{27}\}-3]}$ = $(0.3)^{[2-3]}$ = $(0.3)^{-1}$ = $\frac{1}{0.3}$ = $\frac{10}{3}$ Hence, the correct answer is $\frac{10}{3}$.
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