Question : The value of $\frac{5-[2+3(2-2 \times 2+5)-5] \div 5}{4 \times 4 \div 4 \text { of }(4+4 \div 4 \text { of } 4)}$ is:
Option 1: $3 \frac{3}{16}$
Option 2: $4 \frac{3}{80}$
Option 3: $\frac{2}{5}$
Option 4: $7 \frac{3}{5}$
Correct Answer: $4 \frac{3}{80}$
Solution : $\frac{5-[2+3(2-2 \times 2+5)-5] \div 5}{4 \times 4 \div 4 \text { of }(4+4 \div 4 \text { of } 4)}$ $=\frac{5-[2+3(2-2 \times 2+5)-5] \div 5}{4 \times 4 \div 4 \times(4+4 \div 4 \times4)}$ $=\frac{5-[2+3(3)-5] \div 5}{4 \times 4 \div 4 \times(4+\frac{4}{16})}$ $=\frac{5-[2+9-5] \div 5}{4 \times 4 \times\frac{1}{17}}$ $=\frac{5-\frac{6}{5}}{\frac{16}{17}}$ $=\frac{\frac{19}{5}}{\frac{16}{17}}$ $=\frac{19}{5}\times\frac{17}{16}$ $=\frac{323}{80}$ $=4\frac{3}{80}$ Hence, the correct answer is $4\frac{3}{80}$.
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