Question : The value of $8-3 \div 6$ of $2+\left(4 \div 4\right.$ of $\left.\frac{1}{4}\right) \div 8+\left(4 \times 8 \div \frac{1}{4}\right) \times \frac{1}{8}$ is:
Option 1: $\frac{7}{4}$
Option 2: $-\frac{97}{4}$
Option 3: $-\frac{7}{4}$
Option 4: $\frac{97}{4}$
Correct Answer: $\frac{97}{4}$
Solution :
$8-3 \div 6$ of $2+\left(4 \div 4\right.$ of $\left.\frac{1}{4}\right) \div 8+\left(4 \times 8 \div \frac{1}{4}\right) \times \frac{1}{8}$
= $8-3 \div12+\left(4 \div 1\right.)$ $\div 8+\left(4 \times 8 × {4}\right) \times \frac{1}{8}$
= $8 - \frac{1}{4} + \frac{1}{2} + 16$
= $\frac{(32 - 1 + 2 + 64)}{4}$
= $\frac{97}{4}$
Hence, the correct answer is $\frac{97}{4}$.
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