Question : The value of $1-3 \div 6$ of $2+\left(4 \div 4\right.$ of $\left.\frac{1}{4}\right) \div 8+\left(4 \times 8 \div \frac{1}{4}\right) \times \frac{1}{8}$ is:
Option 1: $\frac{69}{4}$
Option 2: $-\frac{69}{4}$
Option 3: $\frac{7}{4}$
Option 4: $-\frac{7}{4}$
Correct Answer: $\frac{69}{4}$
Solution :
Given: $1-3 \div 6$ of $2+\left(4 \div 4\right.$ of $\left.\frac{1}{4}\right) \div 8+\left(4 \times 8 \div \frac{1}{4}\right) \times \frac{1}{8}$
= $1-3 \div 12+(4 \div 1) \div 8+\left(4 \times 8 \times4\right) \times \frac{1}{8}$
= $1-\frac{3}{12}+\frac{4}{8}+\left(4 \times 8 \times4\right) \times \frac{1}{8}$
= $1-\frac{1}{4}+\frac{1}{2}+16$
= $\frac{4-1+2+64}{4}$
= $\frac{69}{4}$
Hence, the correct answer is $\frac{69}{4}$.
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