Question : The value of $4 \div 12$ of $[3 \div 4$ of $\{(4-2) \times 6 \div 2\}]-2 \times 6 \div 8+3$ is:
Option 1: $4 \frac{1}{6}$
Option 2: $3 \frac{1}{3}$
Option 3: $2 \frac{1}{3}$
Option 4: $7 \frac{1}{6}$
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Correct Answer: $4 \frac{1}{6}$
Solution :
Given: $4 \div 12$ of $[3 \div 4$ of $\{(4-2) \times 6 \div 2\}]-2 \times 6 \div 8+3$
= $4 ÷ (12 × [3 ÷ 24]) – 2 × \frac{6}{8} + 3$
= $4 ÷ \frac{3}{2}−2×\frac{6}{8}+3$
= $\frac{8}{3} - \frac{3}{2} +3$
= $\frac{16-9+18}{6}$
= $\frac{25}{6}$
= $4 \frac{1}{6}$
Hence, the correct answer is $4 \frac{1}{6}$.
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