Question : The volume of a solid sphere is $4500 \pi \;cm^3$. The surface area of the solid sphere is:
Option 1: $700 \pi\; \text{cm}^2$
Option 2: $850 \pi\; \text{cm}^2$
Option 3: $900 \pi\; \text{cm}^2$
Option 4: $810 \pi\; \text{cm}^2$
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Correct Answer: $900 \pi\; \text{cm}^2$
Solution : Volume of a solid sphere = $4500 \pi$ cm$^3$ $⇒\frac{4}{3}×\pi×r^3$ = $4500 \pi$ cm$^3$ $⇒r^3$ = $\frac{4500×3}{4}$ = 3375 $\therefore r$ = 15 cm The Surface area of the solid sphere = $4\pi r^2$ = 4 × $\pi$ × 15$^2$ cm$^2$ = 900$ \pi$ cm$^2$ Hence, the correct answer is $900 \pi\; \text{cm}^2$.
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Question : If the radius of a sphere is increased by 2 cm, then its surface area increases by 352 cm2. The radius of the sphere initially was: (use $\pi =\frac{22}{7}$)
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Question : The area of a circle whose radius is the diagonal of a square whose area is $4\;\mathrm{cm^2}$ is:
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