the wavelength of the first line in balmer series the hydrogen spectrum is lambda what is the wavelength of second line
Answer (1)
20th May, 2020
Hello!!!!
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According to rydberg's equation 1/λ = RZ 2 (1/n 1 2 - 1/n 2 2 )
λ is inversly proportional to n 2
therefore ..;;
λ1/λ2=n2 2 /n1 2
As balmer series start from first line i.e, n1=2,n2=3,λ1=λ ,λ2=?
λ/λ2=3^2/2^2
λ/λ2=9/4
Therefore., wave length of second line in balmer series ,, λ2=4λ/9
Hope it helps !!!!!
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