Question : The weights of two iron balls are 3.5 kg and 7.5 kg. What is the percentage weight of the first ball with respect to the weight of the second ball?
Option 1: $46\frac{2}{3}$%
Option 2: $35$%
Option 3: $46\frac{1}{3}$%
Option 4: $45$%
Correct Answer: $46\frac{2}{3}$%
Solution :
Given: The weights of two iron balls are 3.5 kg and 7.5 kg.
Required percentage = $\frac{\text{weight of the first ball}}{\text{weight of the second ball}} × 100$%
= $\frac{3.5}{7.5} × 100$
= $\frac{140}{3}$
= $46\frac{2}{3}$%
Hence, the correct answer is $46\frac{2}{3}$%.
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