there are 4 5 and 6 points on the parallel and coplanar lines if no set of 4 or more points is cyclic and no set of 3 points lying on distinct lines is collinear,then the no.of circles passing through exactly 3 points is.
Answer (1)
12th Apr, 2022
Hi,
It's mentioned that no more than 4 points can lie on the circle of the circle cannot pass through more than a set of four points.
So, it's obvious that from the parallel lines only one point can be included. Hence, here are the following combinations which can be found-
Case I: 4C1* 5C1*6C2
Case II: 4C1* 5C2*6C1
Case III: 5C2* 6C2
Case IV: 5C3* 6C1
Case V: 6C3* 5C1
Hope this helpful.
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