there are 4 5 and 6 points on the parallel and coplanar lines if no set of 4 or more points is cyclic and no set of 3 points lying on distinct lines is collinear,then the no.of circles passing through exactly 3 points is.
Answer (1)
12th Apr, 2022
Hi,
It's mentioned that no more than 4 points can lie on the circle of the circle cannot pass through more than a set of four points.
So, it's obvious that from the parallel lines only one point can be included. Hence, here are the following combinations which can be found-
Case I: 4C1* 5C1*6C2
Case II: 4C1* 5C2*6C1
Case III: 5C2* 6C2
Case IV: 5C3* 6C1
Case V: 6C3* 5C1
Hope this helpful.
Comments (0)
Related Questions
Know More about
Symbiosis Entrance Test
Eligibility | Application | Admit Card | Result | Preparation Tips | Dates | FAQs
Get Updates Brochure
Thank You!
Your Symbiosis Entrance Test brochure has been successfully mailed to your registered email id “”.
Upcoming Exams
Application Date:
22 Nov, 2024
- 6 Jan, 2025
Application Date:
3 Sep, 2024
- 3 Dec, 2024
Application Date:
16 Sep, 2024
- 4 Dec, 2024
