There are only two womens among 20 person taking part in a pleasure trip. The 20 persons are divided into two groups, each group consisting
Answer (1)
17th Nov, 2018
Total Number of Way of Dividing into Two Groups 20C10=184756 ( Which is same is selecting 10 People from 20)
Since the two women are to be together in the same Group, consider then One
Now two cases arise we will talk of only selecting one group and the other will be made automatically, so we consider two cases in one both the women selected and other No women are selected, in that case, they will be together in the other Group.
If Both the women are selected then we need to select 8 out of 18 that is 18C8=43758
If Both the women are not selected we need to select 10 out of 18 that is 18C10=43758
Therefore Probability is =(43758+43758)/184756=87516/184756=0.47
Therefore 0.47 is the answer.
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