Question : There are three numbers where the first number is twice the second, and the second is thrice the third number. If the average of the three numbers is 20, what is the sum of the largest and smallest numbers?
Option 1: 24
Option 2: 42
Option 3: 54
Option 4: 60
Correct Answer: 42
Solution :
Let the third number be $x$.
According to the question,
The second number $= 3x$ and the first number $= 6x$.
So, $6x + 3x + x = 3 × 20$ (Sum of all three numbers)
⇒ $10x = 60$
⇒ $x = 6$
Therefore, the required sum $= 6x + x= 7x= 7 × 6 = 42$
Hence, the correct answer is 42.
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