Question : There are two numbers such that the first number is three times the second number. If the average of these two numbers is 72, then what is the first number?
Option 1: 108
Option 2: 54
Option 3: 36
Option 4: 64
Correct Answer: 108
Solution :
Let the second number be $x$ and the first three times of the second number be 3$x$
Average = $\frac{\text{Sum of the numbers}}{\text{Number of numbers}}$
⇒ 72 = $\frac{x + 3x}{2}$ = $\frac{4x}{2}$ = 2$x$ = 36
First number = 3$x$
= 3 × 36
= 108
Hence, the correct answer is 108.
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