Question : There are two pumps to fill a tank with water. The first pump can fill the empty tank in 8 hours, while the second in 10 hours. If both the pumps are opened at the same time and kept open for 4 hours, the part of the tank that will be filled up is:
Option 1: $\frac{9}{10}$
Option 2: $\frac{1}{10}$
Option 3: $\frac{2}{5}$
Option 4: $\frac{1}{5}$
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Correct Answer: $\frac{9}{10}$
Solution : Given: The first pump can fill the empty tank in 8 hours, while the second in 10 hours. So, we have part of the tank filled in an hour by both pump $=\frac{1}{8}+\frac{1}{10}=\frac{9}{40}$ $\therefore$ Part of the tank filled in 4 hours $=\frac{4×9}{40}=\frac{9}{10}$ Hence, the correct answer is $\frac{9}{10}$.
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Question : Tap A can fill an empty tank in 8 hours if no other tap is open, and tap B can empty the same tank, when filled, in 12 hours, when no other tap is open. Find the time taken to fill the same tank, when empty, if both the taps are opened together.
Question : Three pipes A, B, and C can fill a tank in 6 hours, 9 hours, and 12 hours, respectively. B and C are opened for half an hour, and then pipe A is opened. The time taken by the three pipes together to fill the remaining part of the tank is:
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