Question : In a two-digit number, the digit at unit's place is 1 less than twice the digit at the ten's place. If the digit at unit's and ten's place are interchanged, the difference between the new and the original number is less than the original number by 20. The

Question : By interchanging the digits of a two-digit number, we get a number which is four times the original number minus 24. If the digit at the unit's place of the original number exceeds its digit at ten's place by 7, then the original number is:

Question : In a two-digit number, the digit at the unit place is 1 less than twice the digit at the tens place. If the digits at the units place and tens places are interchanged, the difference between the new and the original number is less than the original number by 20. The original

Question : What is the value of $\frac{\frac{5}{3} \text { of } \frac{1}{4} \times \frac{24}{5}-\frac{1}{5} \text { of } \frac{25}{8} \times \frac{24}{5}}{\frac{5}{12} \text { of } \frac{3}{4} \times \frac{4}{3}+\frac{3}{4} \text { of } \frac{12}{5} \times \frac{5}{6}}$?

Question : The area of a regular hexagon with side '$a$' is: