Thin spherical conducting shell of radius Rhas charge Qanother charge Q centre of theshell electrostatic potential of P at distance d/2 fron the centre of the shell?
NEET 2024: Cutoff (OBC, SC, ST & General Category)
NEET 2024 Admission Guidance: Personalised | Study Abroad
NEET 2025: Syllabus | Most Scoring concepts | NEET PYQ's (2015-24)
Answer (1)
3rd Sep, 2020
Hello Dear,
- One charge Q is present on the thin spherical shell , so the shell is totally charged Q.
- Second charge Q is placed at the center of the spherical shell.
- Now for potential at point P we have
- Let V1 is potential at P due to Q on spherical shell and let V2 is potential at P due to center charge, let V is total potential at P. So now
V=V1+V2
V=0 + 9*10^9*Q*2/d
V=18*10^9*Q/d
Comments (0)
Related Questions
Know More about
National Eligibility cum Entrance Test
Eligibility | Answer Key | Result | Cutoff | College Predictor | Counselling | Application | Accepting Colleges
Get Updates Brochure
Thank You!
Your National Eligibility cum Entrance Test brochure has been successfully mailed to your registered email id “”.
