Thin spherical conducting shell of radius Rhas charge Qanother charge Q centre of theshell electrostatic potential of P at distance d/2 fron the centre of the shell?
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Answer (1)
3rd Sep, 2020
Hello Dear,
- One charge Q is present on the thin spherical shell , so the shell is totally charged Q.
- Second charge Q is placed at the center of the spherical shell.
- Now for potential at point P we have
- Let V1 is potential at P due to Q on spherical shell and let V2 is potential at P due to center charge, let V is total potential at P. So now
V=V1+V2
V=0 + 9*10^9*Q*2/d
V=18*10^9*Q/d
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