Three consecutive natural numbers are such that the square of the middle no exceeds the difference of the squares of other two by 60findthen
Answer (1)
Student Expert
5th Mar, 2019
Hello Diya
Answer is 9;10;11
Take the numbers as
n-1
n
n+1
Now according to given condition
( n+1)^2 - ( n-1)^2 + 60 = n^2
(n+1+n-1) *( n+1-n+1) +60 = n^2
4*n +60 = n^2
So
n = 10
Good luck.
Answer is 9;10;11
Take the numbers as
n-1
n
n+1
Now according to given condition
( n+1)^2 - ( n-1)^2 + 60 = n^2
(n+1+n-1) *( n+1-n+1) +60 = n^2
4*n +60 = n^2
So
n = 10
Good luck.
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