Three forces F1=2i+j-kN F2=2i+3j-3kN F3=a(i+j-k)N act simultaneously on a particle. The value of 'a' so that particle may be in equilibrium is 1)4 2)-4 3)2 4)6
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Answer (1)
17th Sep, 2020
Hello,
In the question it is stated that to be in equilibrium .In equilibrium their sum should be equal to zero .
So F1+F2+F3=0
2i+j-k+2i+3j-3k+ai+aj-ak=0
(4+a)i+(4+a)j-(4+a)k=0i+0j+0k
If we compare on both the sides
a=-4
Hope this answers helps!
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