Question : Three fractions $x, y$ and $z$ are such that $x > y > z$. When the smallest of them is divided by the greatest, the result is $\frac{9}{16}$, which exceeds $y$ by 0.0625. If $x+y+z=2 \frac{3}{12}$, then what is the value of $x + z$?
Option 1: $\frac{5}{4}$
Option 2: $\frac{3}{4}$
Option 3: $\frac{7}{4}$
Option 4: $\frac{1}{4}$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $\frac{7}{4}$
Solution : Given: $x > y > z$ According to the question, $\frac{z}{x} = \frac{9}{16}$ ⇒ $y = \frac{9}{16}-0.0625=\frac{9}{16}-\frac{1}{16} = \frac{1}{2}$ ⇒ $x+y+z=2 \frac{3}{12}=\frac{27}{12}$ ⇒ $x + \frac{1}{2} + z = \frac{27}{12}$ $\therefore x + z = \frac{27}{12} - \frac{1}{2}= \frac{27-6}{12}= \frac{21}{12}= \frac{7}{4}$ Hence, the correct answer is $\frac{7}{4}$.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : Let $x, y, z$ be fractions such that $x<y<z$. If $z$ is divided by $x$, the result is $\frac{5}{2}$, which exceeds $y$ by $\frac{7}{4}$. If $x+y+z=1 \frac{11}{12}$, then the ratio of $(z-x):(y-x)$ is:
Question : If $x=(0.25)^\frac{1}{2}$, $y=(0.4)^{2}$, and $z=(0.216)^{\frac{1}{3}}$, then:
Question : The value of $\frac{(x-y)^3+(y-z)^3+(z-x)^3}{6(x-y)(y-z)(z-x)}$, where $x \neq y \neq z$, is equal to:
Question : If $x+y+z=0$, then what is the value of $\frac{x^2}{(y z)}+\frac{y^2}{(x z)}+\frac{z^2}{(x y)}$?
Question : If $x^2+y^2=29$ and $xy=10$, where $x>0,y>0$ and $x>y$. Then the value of $\frac{x+y}{x-y}$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile