Question : Three men can complete a piece of work in 6 days. Two days after they started the work, 3 more men joined them. How many days will it take to complete the remaining work?
Option 1: 1 day
Option 2: 2 days
Option 3: 3 days
Option 4: 4 days
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Correct Answer: 2 days
Solution : Given: Three men can complete a piece of work in 6 days. Part of work done in 2 day = $\frac{1}{6}×2=\frac{1}{3}$ Remaining work = $1-\frac{1}{3}=\frac{2}{3}$ We know that: $\frac{M_1 ×D_1}{W_1}=\frac{M_2 ×D_2}{W_2}$ Where $M_1$ and $M_2$ are the numbers of men, and $D_1$ and $D_2$ are days, and $W_1$ and $W_2$ are work done. ⇒ $\frac{3 ×2}{\frac{1}{3}}=\frac{6 ×D_2}{\frac{2}{3}}$ ⇒ $D_2=\frac{12}{3}$ = 2 days Hence, the correct answer is 2 days.
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