To a 50ml of 0.05M formic acid how much volume of 0.10M Sodium formate must be added to get a buffer solution of pH =4.0(pka of acid is 3.8)?
We have, if V ml be the volume of 0.1MHCOONa be mixed to 50ml of 0.05M HCOOH,
[Molarity]= Total volume/Total milimole
 
In mixture [HCOONa]= (V+50)/(0.1×V)
[HCOOH]= (V+50)/(50×0.05)
As pH =−log(K a ) + log( [Acid]/[Salt)
 
∴ 4.0=3.70+log (V+50)/(2.5)/ (V+50)/ (0.1×V)
So v= approx. 50ml
Hope you understand this!
 
																   
																 
								





 
                
             
                    
                 
								 
								 
								 
								 
								