Hello Aspirant,

Since you have not mentioned the name of colleges but it seems to be NIT Surathakal, if wrong then please mention the correct one.

As we go through the latest cut-off of 2020 then it shows that the closing CRL rank was 3115 for Computer Science and Engineering branch in NIT Surathakal under Home state quota for Open or General category.

Now to secure such rank you should have your JEE-Main  score at least 180+ marks out of 300 and percentile against this should be around 99.7+ .

You can check out the latest cut-offs from the link given below :-

https://josaa.nic.in/Result/Result/currentorcr.aspx

You can check out marks Vs ranks Vs Percentile from the link given below :-

https://engineering.careers360.com/articles/jee-main-marks-vs-percentil e

Or

You can also use JEE-Main Rank Predictor to predict your rank :-

Note that the above prediction is made on the basis of latest cut-offs available on official website of JOSAA or CSAB and the cut-offs are bound to change every year depending upon various factors such as the number of candidates appearing in an examination, the number of candidates qualifying an examination, difficulty level of the paper, and so on.

To have a list of all those colleges which you can get based upon your score, category, and state you can use JEE-Main College Predictor :-

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

As you are preparing for JEE-Main then I would recommend you to check the resources made by our experts to help aspirants like you in the best and smart preparation of JEE-Main :-

https://learn.careers360.com/jee-main-coaching/?utm_source=%20QnA

I hope this information helps you.

Good Luck!!