Question : Two chords AB and CD of a circle intersect each other at P internally. If AP = 3.5 cm, PC = 5 cm, and DP = 7 cm, then what is the measure of PB?
Option 1: 8 cm
Option 2: 12 cm
Option 3: 10 cm
Option 4: 10.5 cm
Correct Answer: 10 cm
Solution :
AP = 3.5 cm PC = 5 cm DP = 7 cm AP × PB = PC × PD 3.5 × PB = 5 × 7 ⇒ PB = $\frac{35}{3.5}$ ⇒ PB = 10 cm Hence, the correct answer is 10 cm.
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