Question : Two chords AB and CD of a circle intersect each other at P internally. If AP = 3.5 cm, PC = 5 cm, and DP = 7 cm, then what is the measure of PB?
Option 1: 8 cm
Option 2: 12 cm
Option 3: 10 cm
Option 4: 10.5 cm
Answer (1)
26th Jan, 2024
Correct Answer: 10 cm
Solution :
AP = 3.5 cm
PC = 5 cm
DP = 7 cm
AP × PB = PC × PD
3.5 × PB = 5 × 7
⇒ PB = $\frac{35}{3.5}$
⇒ PB = 10 cm
Hence, the correct answer is 10 cm.
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