Question : Two circles C1 and C2 touch each other internally at P. Two lines PCA and PDB meet the circles C1 in C, D, and C2 in A, B respectively. If $\angle$BDC=120°, then the value of $\angle$ABP is equal to
Option 1: 60°
Option 2: 80°
Option 3: 100°
Option 4: 120°
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Correct Answer: 60°
Solution :
Given $\angle$BDC = 120°
Then, $\angle$CDP = 180° – 120° = 60°
Here, CD || AB
So, $\angle$CDP = $\angle$ABP
$\therefore$ $\angle$ABP = 60°
Hence, the correct answer is 60°.
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